Different types of hydraulic motors use different methods to pump their fluids. Some grind gears together. Some use a combination of cylinders. Some contain vanes that slide in and out of a circular rotor. But ultimately, the various systems all end up forcing the fluid through a cavity to an outlet. The size of this cavity contributes to how much fluid the motor pumps each minute. The other determining factor is the fluid's linear speed.
Multiply the proposed volumetric flow rate, measured in gallons per minute, by the set conversion value 231. With a proposed flow rate, for instance, of 40 gallons per minute: 40 x 231 = 9,240.
Divide the answer by the fluid's linear speed, measured in feet per second. If the fluid will move, for instance, at 0.018 feet per second, then 9,240 / 0.018 = 513,333.
Divide the result by 720, a figure that relates feet per second to inches per minute: 513,333 / 720 = approximately 713 square inches. This is the pump's necessary cross-sectional area.
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