Things You'll Need:
- Paper Pencil
-
Step 1
conversion of two triangle into a parallelogramDetermine the area of a triangle when the base and height are known. Take any two identical triangles with base s and height h. We can always form a parallelogram of base s and height h with these two triangles. Since the area of a parallelogram is s x h, the area A of a triangle is therefore ½ s x h.
-
Step 2
Form the equilateral triangle into two right triangles with the line segment h. The hypotenuse of one of these right triangles length s, one of the legs has length h and the other leg has length s/2.
-
Step 3
Express h in terms of s. Using the right triangle formed in step 2, we know that s^2 = (s/2)^2 + h^2 by the Pythagorean formula. Therefore, h^2 = s^2 -- (s/2)^2 = s^2 -- s^2/4 = 3s^2/4, and we now have h = (3^1/2)s/2.
-
Step 4
Substitute the value of h obtained in step 3 into the formula for a triangle's area obtained in step 1. Since A = ½ s x h and h = (3^1/2)s/2, we now have A = ½ s (3^1/2)s/2 = (3^1/2)(s^2)/4.
-
Step 5
Use the formula for area of an equilateral triangle obtained in step 4 to find the area of an equilateral triangle with sides of length 2. A = (3^1/2)(s^2)/4 = (3^1/2)(2^2)/4 = (3^1/2).












